Active Users Problem

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+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| name          | varchar |
+---------------+---------+
the id is the primary key for this table.
This table contains the account id and the user name of each account.

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+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| login_date    | date    |
+---------------+---------+
There is no primary key for this table, it may contain duplicates.
This table contains the account id of the user who logged in and the login date. A user may log in multiple times in the day.

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Accounts table:
+----+----------+
| id | name     |
+----+----------+
| 1  | Winston  |
| 7  | Jonathan |
+----+----------+

Logins table:
+----+------------+
| id | login_date |
+----+------------+
| 7  | 2020-05-30 |
| 1  | 2020-05-30 |
| 7  | 2020-05-31 |
| 7  | 2020-06-01 |
| 7  | 2020-06-02 |
| 7  | 2020-06-02 |
| 7  | 2020-06-03 |
| 1  | 2020-06-07 |
| 7  | 2020-06-10 |
+----+------------+

Result table:
+----+----------+
| id | name     |
+----+----------+
| 7  | Jonathan |
+----+----------+
User Winston with id = 1 logged in 2 times only in 2 different days, so, Winston is not an active user.
User Jonathan with id = 7 logged in 7 times in 6 different days, five of them were consecutive days, so, Jonathan is an active user.

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select a.id, a.name
from Accounts a
where a.id in
    (select l.id
    from (select distinct l.id, l.login_date,
              datediff(l.login_date, '1970-01-01') - dense_rank() over(partition by l.id order by l.login_date) as rk_group
          from Logins l) l
    group by l.rk_group, l.id
    having count(l.login_date) >= 5)
order by a.id