Bank Account Summary II Problem
Description
LeetCode Problem 1587.
Table: Users
1
2
3
4
5
6
7
8
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| account | int |
| name | varchar |
+--------------+---------+
account is the primary key for this table.
Each row of this table contains the account number of each user in the bank.
Table: Transactions
1
2
3
4
5
6
7
8
9
10
11
12
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| trans_id | int |
| account | int |
| amount | int |
| transacted_on | date |
+---------------+---------+
trans_id is the primary key for this table.
Each row of this table contains all changes made to all accounts.
amount is positive if the user received money and negative if they transferred money.
All accounts start with a balance 0.
Write an SQL query to report the name and balance of users with a balance higher than 10000. The balance of an account is equal to the sum of the amounts of all transactions involving that account.
Return the result table in any order.
The query result format is in the following example.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
Users table:
+------------+--------------+
| account | name |
+------------+--------------+
| 900001 | Alice |
| 900002 | Bob |
| 900003 | Charlie |
+------------+--------------+
Transactions table:
+------------+------------+------------+---------------+
| trans_id | account | amount | transacted_on |
+------------+------------+------------+---------------+
| 1 | 900001 | 7000 | 2020-08-01 |
| 2 | 900001 | 7000 | 2020-09-01 |
| 3 | 900001 | -3000 | 2020-09-02 |
| 4 | 900002 | 1000 | 2020-09-12 |
| 5 | 900003 | 6000 | 2020-08-07 |
| 6 | 900003 | 6000 | 2020-09-07 |
| 7 | 900003 | -4000 | 2020-09-11 |
+------------+------------+------------+---------------+
Result table:
+------------+------------+
| name | balance |
+------------+------------+
| Alice | 11000 |
+------------+------------+
Alice's balance is (7000 + 7000 - 3000) = 11000.
Bob's balance is 1000.
Charlie's balance is (6000 + 6000 - 4000) = 8000.
MySQL Solution
1
2
3
4
5
6
7
select name, balance
from (select account, sum(amount) as balance
from Transactions
group by account
having sum(amount) > 10000) t
join Users u
on u.account = t.account;
LeetCode Database - Easy
LeetCode 1407
LeetCode 1435
LeetCode 1484
LeetCode 1495
LeetCode 1511
LeetCode 1517
LeetCode 1527
LeetCode 1543
LeetCode 1565
LeetCode 1571
LeetCode 1581
LeetCode 1587
LeetCode 1607
LeetCode 1623
LeetCode 1633
LeetCode 1661
LeetCode 1667
LeetCode 1677
LeetCode 1683
LeetCode 1693
LeetCode 1729
LeetCode 1731
LeetCode 1741
LeetCode 1757
LeetCode 1777
LeetCode 1789
LeetCode 1795
LeetCode 1809
More LeetCode Database
MySQL Tutorials