# All People Report To The Given Manager Problem

## Description

LeetCode Problem 1270.

Table: Employees

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+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| employee_id   | int     |
| employee_name | varchar |
| manager_id    | int     |
+---------------+---------+
employee_id is the primary key for this table.
Each row of this table indicates that the employee with ID employee_id and name employee_name reports his work to his/her direct manager with manager_id
The head of the company is the employee with employee_id = 1.
``````

Write an SQL query to find employee_id of all employees that directly or indirectly report their work to the head of the company.

The indirect relation between managers will not exceed 3 managers as the company is small.

Return result table in any order without duplicates.

The query result format is in the following example:

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Employees table:
+-------------+---------------+------------+
| employee_id | employee_name | manager_id |
+-------------+---------------+------------+
| 1           | Boss          | 1          |
| 3           | Alice         | 3          |
| 2           | Bob           | 1          |
| 4           | Daniel        | 2          |
| 7           | Luis          | 4          |
| 8           | Jhon          | 3          |
| 9           | Angela        | 8          |
| 77          | Robert        | 1          |
+-------------+---------------+------------+

Result table:
+-------------+
| employee_id |
+-------------+
| 2           |
| 77          |
| 4           |
| 7           |
+-------------+

The head of the company is the employee with employee_id 1.
The employees with employee_id 2 and 77 report their work directly to the head of the company.
The employee with employee_id 4 report his work indirectly to the head of the company 4 --> 2 --> 1.
The employee with employee_id 7 report his work indirectly to the head of the company 7 --> 4 --> 2 --> 1.
The employees with employee_id 3, 8 and 9 don't report their work to head of company directly or indirectly.
``````

## MySQL Solution

``````1
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select a.employee_id
from employees a
join employees b
join employees c
where a.manager_id = b.employee_id and
b.manager_id = c.employee_id and
c.manager_id = 1 and
a.employee_id != c.manager_id
``````