Exam Room Problem


Description

LeetCode Problem 855.

There is an exam room with n seats in a single row labeled from 0 to n - 1.

When a student enters the room, they must sit in the seat that maximizes the distance to the closest person. If there are multiple such seats, they sit in the seat with the lowest number. If no one is in the room, then the student sits at seat number 0.

Design a class that simulates the mentioned exam room.

Implement the ExamRoom class:

  • ExamRoom(int n) Initializes the object of the exam room with the number of the seats n.
  • int seat() Returns the label of the seat at which the next student will set.
  • void leave(int p) Indicates that the student sitting at seat p will leave the room. It is guaranteed that there will be a student sitting at seat p.

Example 1:

1
2
3
4
5
6
7
8
9
10
11
12
13
Input
["ExamRoom", "seat", "seat", "seat", "seat", "leave", "seat"]
[[10], [], [], [], [], [4], []]
Output
[null, 0, 9, 4, 2, null, 5]
Explanation
ExamRoom examRoom = new ExamRoom(10);
examRoom.seat(); // return 0, no one is in the room, then the student sits at seat number 0.
examRoom.seat(); // return 9, the student sits at the last seat number 9.
examRoom.seat(); // return 4, the student sits at the last seat number 4.
examRoom.seat(); // return 2, the student sits at the last seat number 2.
examRoom.leave(4);
examRoom.seat(); // return 5, the student sits at the last seat number 5.

Constraints:

  • 1 <= n <= 10^9
  • It is guaranteed that there is a student sitting at seat p.
  • At most 10^4 calls will be made to seat and leave.


Sample C++ Code

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
class ExamRoom {
private:
    set<int> seats;
    int capacity;

public:
    // 1. Ordered set is used to store occupied seats
    // 2. Distance between candidate seat and the nearest seat is calculated as below:
    // (1) If end seats 0 or n-1 are empty, the distance between the nearest seat is 
    // same as difference between occupied seat and the end candidate seat
    // (2) For seats in between. the distance is half way between two occupied seats
    ExamRoom(int N) {
        capacity = N;
    }

    int seat() {
        int dist = 0;
        int curr = 0;

        if (!seats.empty()) {
            auto itr = seats.begin();
            
            //calculate distance at the begining
            dist = *itr;
            if (dist == 0) {
                itr ++;
            }

            //calculate distance in between
            while (itr != seats.end()) {
                int mid_dist = (*itr - *prev(itr)) / 2;
                if (dist < mid_dist) {
                    dist = mid_dist;
                    curr = *prev(itr) + dist;
                }
                itr ++;
            }
            
            //calculate distance at the end
            if (dist < ((capacity - 1) - *(seats.rbegin()))) {
                curr = capacity - 1;
            }
        }

        return *(seats.insert(curr).first);
    }

    void leave(int p) {
        seats.erase(p);
    }
};

/**
 * Your ExamRoom object will be instantiated and called as such:
 * ExamRoom* obj = new ExamRoom(n);
 * int param_1 = obj->seat();
 * obj->leave(p);
 */




Related Posts

Time Based Key-Value Store Problem

LeetCode 981. Design a time-based key-value data structure that can...

Rle Iterator Problem

LeetCode 900. We can use run-length encoding (i.e., RLE) to...

Online Stock Span Problem

LeetCode 901. Design an algorithm that collects daily price quotes...

Online Election Problem

LeetCode 911. You are given two integer arrays persons and...

Number Of Recent Calls Problem

LeetCode 933. You have a RecentCounter class which counts the...

Maximum Frequency Stack Problem

LeetCode 895. Design a stack-like data structure to push elements...