# Rectangle Overlap Problem

## Description

LeetCode Problem 836.

An axis-aligned rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) is the coordinate of its bottom-left corner, and (x2, y2) is the coordinate of its top-right corner. Its top and bottom edges are parallel to the X-axis, and its left and right edges are parallel to the Y-axis.

Two rectangles overlap if the area of their intersection is positive. To be clear, two rectangles that only touch at the corner or edges do not overlap.

Given two axis-aligned rectangles rec1 and rec2, return true if they overlap, otherwise return false.

Example 1:

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Input: rec1 = [0,0,2,2], rec2 = [1,1,3,3]
Output: true

Example 2:

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Input: rec1 = [0,0,1,1], rec2 = [1,0,2,1]
Output: false

Example 3:

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Input: rec1 = [0,0,1,1], rec2 = [2,2,3,3]
Output: false

Constraints:

- rect1.length == 4
- rect2.length == 4
- -10^9 <= rec1[i], rec2[i] <= 10^9
- rec1 and rec2 represent a valid rectangle with a non-zero area.

## Sample C++ Code

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class Solution {
public:
bool isRectangleOverlap(vector<int>& rec1, vector<int>& rec2) {
int x1 = max(rec1[0],rec2[0]);
int y1 = max(rec1[1],rec2[1]);
int x2 = min(rec1[2],rec2[2]);
int y2 = min(rec1[3],rec2[3]);
if(x1 < x2 && y1 < y2)
return true;
return false;
}
};