# Sales Analysis I Problem

## Description

LeetCode Problem 1082.

Table: Product

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+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| product_id   | int     |
| product_name | varchar |
| unit_price   | int     |
+--------------+---------+
product_id is the primary key of this table.
``````

Table: Sales

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+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| seller_id   | int     |
| product_id  | int     |
| buyer_id    | int     |
| sale_date   | date    |
| quantity    | int     |
| price       | int     |
+------ ------+---------+
This table has no primary key, it can have repeated rows.
product_id is a foreign key to Product table.
``````

Write an SQL query that reports the best seller by total sales price. If there is a tie, report them all.

The query result format is in the following example:

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Product table:
+------------+--------------+------------+
| product_id | product_name | unit_price |
+------------+--------------+------------+
| 1          | S8           | 1000       |
| 2          | G4           | 800        |
| 3          | iPhone       | 1400       |
+------------+--------------+------------+

Sales table:
+-----------+------------+----------+------------+----------+-------+
| seller_id | product_id | buyer_id | sale_date  | quantity | price |
+-----------+------------+----------+------------+----------+-------+
| 1         | 1          | 1        | 2019-01-21 | 2        | 2000  |
| 1         | 2          | 2        | 2019-02-17 | 1        | 800   |
| 2         | 2          | 3        | 2019-06-02 | 1        | 800   |
| 3         | 3          | 4        | 2019-05-13 | 2        | 2800  |
+-----------+------------+----------+------------+----------+-------+

Result table:
+-------------+
| seller_id   |
+-------------+
| 1           |
| 3           |
+-------------+
Both sellers with id 1 and 3 sold products with the most total price of 2800.
``````

## MySQL Solution

``````1
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select distinct seller_id
from Sales
group by seller_id
having sum(price) = (
select sum(price) as max_price
from Sales
group by seller_id
order by max_price desc
limit 1)
``````

The second select statement is to a subquery to calculate the maximum sales price. The first select statement is to pick sellers that have the best total sales price.